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... the X Direction therefore the resultant Force along the X direction should be zero which equals to normal force minus T1 is the force in this yellow cable so if we draw the kinetic diagram it is moving up Update: I realized that there's an inconsistency in the problem statement image: at t=15 s, acceleration value is not 30. But the ...

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  • So in this problem we have two blocks a and B
  • ... which equals to the force F minus the weight Force has two components so this component right here this one equals to
  • Let's look at this problem this is actually from my

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